(x^3+12xy+12y^2)-(8x^3+2xy+7y^2)=0

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Solution for (x^3+12xy+12y^2)-(8x^3+2xy+7y^2)=0 equation: 


Simplifying
(x3 + 12xy + 12y2) + -1(8x3 + 2xy + 7y2) = 0

Reorder the terms:
(12xy + x3 + 12y2) + -1(8x3 + 2xy + 7y2) = 0

Remove parenthesis around (12xy + x3 + 12y2)
12xy + x3 + 12y2 + -1(8x3 + 2xy + 7y2) = 0

Reorder the terms:
12xy + x3 + 12y2 + -1(2xy + 8x3 + 7y2) = 0
12xy + x3 + 12y2 + (2xy * -1 + 8x3 * -1 + 7y2 * -1) = 0
12xy + x3 + 12y2 + (-2xy + -8x3 + -7y2) = 0

Reorder the terms:
12xy + -2xy + x3 + -8x3 + 12y2 + -7y2 = 0

Combine like terms: 12xy + -2xy = 10xy
10xy + x3 + -8x3 + 12y2 + -7y2 = 0

Combine like terms: x3 + -8x3 = -7x3
10xy + -7x3 + 12y2 + -7y2 = 0

Combine like terms: 12y2 + -7y2 = 5y2
10xy + -7x3 + 5y2 = 0

Solving
10xy + -7x3 + 5y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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